NCERT Solutions for Class 8 Maths Chapter 14 Factorisation

NCERT Solutions for Class 8 Maths Chapter 14 Factorisation, are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 14 Factorisation.

NCERT Solutions for Class 8 Maths Chapter 14 Factorisation

NCERT Solutions for Class 8 Maths Chapter 14 Factorisation Ex 14.1

Question 1.
Find the common factors of the given terms:

Solution.

Question 2.
Factorise the following expressions:

Solution.

Question 3.
Factorise:

Solution.

NCERT Solutions for Class 8 Maths Chapter 14 Factorisation Ex 14.2

Question 1.
Factorise the following expressions:

Solution.

Question 2.
Factorise:

Solution.

Question 3.
Factorise the expressions:

Solution.

Question 4.
Factorise:

Solution.

Question 5.
Factorise the following expressions:

Solution.

NCERT Solutions for Class 8 Maths Chapter 14 Factorisation Ex 14.3

Question 1.
Carry out the following divisions:

Solution.

Question 2.
Divide the given polynomial by the given monomial:

Solution.

Question 3.
Work out the following divisions:

Solution.

Question 4.
Divide as directed.

Solution.

Question 5.
Factorise the expressions and divide them as directed.

Solution.

NCERT Solutions for Class 8 Maths Chapter 14 Factorisation Ex 14.4

Find and correct the errors in the following mathematical statements.
Question 1.
4(x – 5) = 4x – 5
Solution.
4(x – 5) = 4x – 20

Question 2.
x(3x + 2) = ${ 3x }^{ 2 }+2$
Solution.
x(3x + 2) = ${ 3x }^{ 2 }+2x$

Question 3.
2x + 3y = 5xy
Solution.
2x + 3y = 2x + 3y

Question 4.
x + 2x + 3x = 5x
Solution.
x + 2x + 3x = 6x

Question 5.
5y + 2y + y – 7y = 0
Solution.
5y + 2y + y – 7y – y

Question 6.
3x + 2x = ${ 5x }^{ 2 }$
Solution..
3x + 2x = 5x

Question 7.
${ \left( 2x \right) }^{ 2 } + 4(2x) + 7 = { 2x }^{ 2 } + 8x + 7$
Solution.
${ \left( 2x \right) }^{ 2 } + 4(2x) + 7 = { 4x }^{ 2 } + 8x + 7$

Question 8.
${ \left( 2x \right) }^{ 2 } + 5x = 4x + 5x = 9x$
Solution.
${ \left( 2x \right) }^{ 2 } + 5x = { 4x }^{ 2 } + 5x$

Question 9.
${ \left( 3x+2 \right) }^{ 2 } = { 3x }^{ 2 } + 6x + 4.$
Solution.
${ \left( 3x+2 \right) }^{ 2 } = { 9x }^{ 2 }+ 12x + 4.$

Question 10.
Substituting x = – 3 in

Solution.

Question 11.
${ \left( y-3 \right) }^{ 2 } = { y }^{ 2 } – 9$
Solution.
${ \left( y-3 \right) }^{ 2 } = { y }^{ 2 } – 2(y)(3) + { 3 }^{ 2 }$
= ${ y }^{ 2 } – 6y + 9$
and not equal to ${ y }^{ 2 } – 9$

Question 12.
${ \left( z+5 \right) }^{ 2 } = { z }^{ 2 } + 25$
Solution.
${ \left( z+5 \right) }^{ 2 } = { z }^{ 2 } + 2(z) (5) + { 5}^{ 2 }$
= ${ z }^{ 2 } + 10z + 25$
and not equal to ${ z }^{ 2 } + 25$

Question 13.
$\left( 2a+36 \right) \left( a-b \right) = { 2a }^{ 2 }-{ 3b }^{ 2 }$
Solution.

Question 14.
$\left( a+4 \right) \left( a+2 \right) = { a}^{ 2 } + 8$
Solution.

Question 15.
$\left( a-4 \right) \left( a-2 \right) = { a}^{ 2 }-8$
Solution.

Question 16.
$\frac { { 3x }^{ 2 } }{ { 3x }^{ 2 } } =0$
Solution.
$\frac { { 3x }^{ 2 } }{ { 3x }^{ 2 } } =1$ and not equal to 0

Question 17.
$\frac { { 3x }^{ 2 }+1 }{ { 3x }^{ 2 } } =1+1=2$
Solution.
$\frac { { 3x }^{ 2 }+1 }{ { 3x }^{ 2 } } =\frac { { 3x }^{ 2 } }{ { 3x }^{ 2 } } +\frac { 1 }{ { 3x }^{ 2 } }$
=$1+\frac { 1 }{ { 3x }^{ 2 } }$ and not equal to 1 + 1 = 2

Question 18.
$\frac { 3x }{ 3x+2 } =\frac { 1 }{ 2 }$
Solution.
$\frac { 3x }{ 3x+2 } =\frac { 3x }{ 3x+2 }$ and not equal to $\frac { 1 }{ 2 }$

Question 19.
$\frac { 3 }{ 4x+3 } =\frac { 1 }{ 4x }$
Solution.
$\frac { 3 }{ 4x+3 } =\frac { 3 }{ 4x+3 }$ and not equal to $\frac { 1 }{ 4x }$

Question 20.
$\frac { 4x+5 }{ 4x } =5$
Solution.
$\frac { 4x+5 }{ 4x } =\frac { 4x }{ 4x } +\frac { 5 }{ 4x } =1+\frac { 5 }{ 4x }$ and not equal to 5

Question 21.
$\frac { 7x+5 }{ 5 } =7x$
Solution.
$\frac { 7x+5 }{ 5 } =\frac { 7x }{ 5 } +\frac { 5 }{ 5 } =\frac { 7x }{ 5 } +1$ and not equal to 7x

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