NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.1, are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.1.
NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Ex 12.1
Question 1.
Get the algebraic expressions in the following cases using variables, constants and arithmetic operations.
- Subtraction of z from y.
- One-half of the sum of numbers x and y.
- The number z multiplied by itself
- One-fourth of the product of numbers p and q.
- Numbers x and y both squared and added.
- Number 5 added to three times the product of numbers m and n.
- Product of numbers y and z subtracted from 10.
- Sum of numbers a and b subtracted from their product.
Solution:
- y – z
- \(\frac { 1 }{ 2 } \) ( x + y )
- z2
- \(\frac { 1 }{ 4 } \) pq
- x2 + y2
- 3mn + 5
- 10 – yz
- ab – ( a + b )
Question 2.
(i) Identify the terms and their factors in the following expressions. Show the terms and factors by tree diagrams :
(a) x – 3
(b) 1 + x + x2
(c) y – y3
(d) 5xy2 + 7x2y
(e) -ab + 2b2 -3a2
(ii) Identify terms and factors in the expressions given below :
(a) – 4x + 5
(b) – 4x + 5y
(c) 5y + 3y2
(d) xy + 2x2y2
(e) pq + q
(f) 1.2 ab -2.4 b + 3.6 a
(g) \(\frac { 3 }{ 4 } \) x + \(\frac { 1 }{ 4 } \)
(h) 0.1 p2 + 0.2 q2
Solution:
Question 3.
Identify the numerical coefficients of terms (other than constants) in the following expressions :
- 5 – 3t2
- 1 + t + t2 + t3
- x + 2xy + 3y
- 100m + 1000n
- -p2q2 + 7pq
- 1.2 a + 0.8 b
- 3.14 r2
- 2 (l + b)
- 0.1 y + 0.01 y2.
Solution:
Question 4.
(a) Identify terms which contain x and give the coefficient of x.
- y2x + y
- 13y2 – 8yx
- x + y + 2
- 5 + z + zx
- 1 + x + xy
- 12xy2 + 25
- 7x + xy2.
(b) Identify terms which contain y2 and give the coefficient of y2.
- 8 – xy2
- 5y2 + 7x
- 2x2y – 15xy2 + 7y2
Solution:
Question 5.
Classify into monomials, binomials and trinomials.
- 4y – 7z
- y2
- x + y – xy
- 100
- ab – a – b
- 5 – 3t
- 4p2q – 4pq2
- 7mn
- z2 – 3z + 8 a2 + b2
- z2 + z
- 1 + x+ x2
Solution:
(i) 4y – 7z.
This expression is a binomial because it contains two terms : 4y and – Iz.
(ii) y2.
This expression is a monomial because it contains only one term : y2
(iii) x + y – xy.
This expression is a trinomial because it contains three terms : x, y and – xy.
(iv) 100.
This expression is a monomial because it contains only one term : 100
(v) ab – a – b.
This expression is a trinomial because it contains three terms : ab,-a and -b
(vi) 5 – 3t.
This expression is a binomial because it contains two terms : 5 and – 31.
(vii) 4p2q – 4pq2.
This expression is a binomial because it contains two terms: 4p2q and – 4pq2.
(viii) 7mn.
This expression is a monomial because it contains only one term : 7mn.
(ix) z2 – 3z + 8.
This expression is a trinomial because it contains three terms : z2, – 3z and 8.
(x) a2 + b2.
This expression is a binomial because it contains two terms : a2 and b2.
(xi) z2 + z.
This expression is a binomial because it contains two terms : z2 and z.
(xii) 1 + x + x2.
This expression is a trinomial because j it contains three terms : 1, x and x2.
Question 6.
State whether a given pair of terms j is of like or unlike terms :
- 1,100
- -7x, \(\frac { 5 }{ 2 } \) x
- -29 x, -29 y
- 14 xy, 42 yx
- 4m2p, 4mp2
- 12xz, 12x2 z2.
Solution:
- Like
- Like
- Unlike
- Like
- Unlike
- Unlike
Question 7.
Identify like terms in the following :
Solution:
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