NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3, are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3.
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3
Question 1.
Construct ADEF such that DE = 5 cm, DF 3 cm, and m ∠EDF = 90°.
Solution:
Steps of Construction
- Draw a line segment DE of length 5 cm.
- At D, draw DX making 90° with DE.
- With D as centre, draw an arc of radius 3 cm. It cuts DX at the point F.
- Join FE.
∆ DEF is now obtained.
Question 2.
Construct an isosceles triangle in which the length of each of its equal sides is 6.5 cm and the angle between them is 110°.
Solution:
Steps of Construction
- Draw a line segment QR of length 6.5 cm.
- At Q, draw QX making 110° with QR, using a protractor.
- With Q as centre, draw an arc of radius 6.5 cm. It cuts QX at P.
- Join PR
∆ PQR is now obtained.
Question 3.
Construct ∆ ABC with BC = 7.5 cm, AC = 5 cm and m ∠C = 60°.
Solution:
Steps of Construction
- Draw a line segment BC of length 7.5 cm.
- At C, draw CX making 60° with CB
- With C as centre, draw an arc of radius 5 cm. It cuts CX at A.
- Join AB. ∆ ABC is now obtained.
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